What are the six trig function values of # (5pi)/3#?

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Nghi N Share
May 17, 2018

Use trig table and unit circle -->
#sin ((5pi)/3) = sin (-pi/3 + (6pi)/3) = sin (-pi/3) = - sin pi/3 = - sqrt3/2#
#cos ((5pi)/3) = cos (-pi/3 + 2pi) = cos (-pi/3) = cos (pi/3) = 1/2#
#tan ((5pi)/3) = sin/(cos) = (sqrt3/2)(2/1) = sqrt3#
#cot ((5pi)/3) = 1/(tan) = 1/sqrt3 = sqrt3/3#
#sec ((5pi)/3) = 1/(cos) = 2#
#csc ((5pi)/3) = 1/(sin) = 2/sqrt3 = 2sqrt3/3#

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