# What are the solutions of 3x^2 + 14x + 8 = 0?

Mar 13, 2016

$x = - \frac{2}{3} , - 4$

#### Explanation:

color(blue)(3x^2+14x+8=0

This is a Quadratic equation (in form $a {x}^{2} + b x + c = 0$)

color(brown)(x=(-b+-sqrt(b^2-4ac))/(2a)

Where

color(red)(a=3,b=14,c=8

Substitute the values in the formula

$\rightarrow x = \frac{- \left(14\right) \pm \sqrt{{14}^{2} - 4 \left(3\right) \left(8\right)}}{2 \left(3\right)}$

$\rightarrow x = \frac{- 14 \pm \sqrt{196 - 96}}{6}$

$\rightarrow x = \frac{- 14 \pm \sqrt{100}}{6}$

rarrcolor(orange)(x=(-14+-10)/(6)

Now we have $2$ values for $x$

color(indigo)(1))color(green)(x=(-14+10)/6=-4/6=-2/3

color(indigo)(2))color(green)(x=(-14-10)/(6)=-24/6=-4