# What are the x intercepts for y − x^2 = −6x − 7?

You can find the intercepts by selling $y = 0$ in your equation and solving for $x$ the second degree equation:
${x}^{2} - 6 x - 7 = 0$
${x}_{1 , 2} = \frac{6 \pm \sqrt{36 - 4 \left(1 \cdot - 7\right)}}{2 \cdot 1} = \frac{6 \pm 8}{2}$
${x}_{1} = 7$
${x}_{2} = - 1$
$\left(7 , 0\right)$
$\left(- 1 , 0\right)$