What does #((3-2i)*(5-6i))/i# equal?
1 Answer
Mar 18, 2018
Explanation:
#color(orange)"Reminder"color(white)(x)i^2=(sqrt(-1))^2=-1#
#"expand the factors on the numerator"#
#rArr(15-28i+12i^2)/i#
#=(3-28i)/i#
#"multiply numerator/denominator by "i#
#=(i(3-28i))/i^2#
#=(28+3i)/(-1)=-28-3i#
