What does #(6-3i)/(2+i)# equal?
1 Answer
Nov 3, 2015
Explanation:
Multiply numerator and denominator by the conjugate of the denominator to find:
#(6-3i)/(2+i) = ((6-3i)(2-i))/((2+i)(2-i)) = (9-12i)/(4+1) = 9/5-12/5i#
