# What happens during redox reactions?

Mar 24, 2018

Stuff....

#### Explanation:

And by stuff we mean $\text{FORMAL ELECTRON TRANSFER....}$

We conceive of $\text{oxidation}$ as the formal loss of electrons...and typically, metals, electron-rich substances, are oxidized...

$M g \left(s\right) \rightarrow M {g}^{2 +} + 2 {e}^{-}$ $\left(i\right)$

Electrons are included as particles of convenience.

And $\text{reduction}$ is the FORMAL gain of electrons, and typically, non-metals, elements from the right hand side of the Periodic Table as we face it, with HIGH nuclear charge, are reduced...

$\frac{1}{2} {O}_{2} + 2 {e}^{-} \rightarrow {O}^{2 -}$ $\left(i i\right)$

We add the two equations together in such a way that the electrons, as formal particles, are ELIMINATED...$\left(i\right) + \left(i i\right)$ gives...

$M g \left(s\right) + \frac{1}{2} {O}_{2} \rightarrow M g O \left(s\right)$