What is #2sqrt45# expressed in simplest radical form?

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Answer 1 · 2016-10-28T03:42:01

#2 sqrt 45=6sqrt 5#

Simplify: #2 sqrt 45#

Determine the prime factorization of #sqrt 45#.

#sqrt 45=sqrt(5xx9)=sqrt 5sqrt9=sqrt 5xx3xx3#

#3# is the square root of #9# or #3xx3#.

Simplify.

#sqrt 45=3sqrt 5#

Multiply #2xx3sqrt5#

Simplify: #6sqrt 5#