What is #(- 6+ | - 3| ) \cdot ( 4- 3\cdot 2) \div ( | - 2| )#?

1 Answer
Jun 21, 2017

Answer:

3

Explanation:

The absolute value of #-3# is #3#.

The absolute value of #-2# is #2#.

Let's rewrite the equation

#(-6+3)*(4-3*2)div(2)#

Let's solve the LHS bracket.

#-6+3=-3#

#-3*(4-3*2)div(2)#

Now, the middle bracket.

#4-3*2# ←  You have to multiply first
#4-6#
#-2#

#-3*-2div(2)#
#6div2#
#3#