# What is (- 6+ | - 3| ) \cdot ( 4- 3\cdot 2) \div ( | - 2| )?

Jun 21, 2017

3

#### Explanation:

The absolute value of $- 3$ is $3$.

The absolute value of $- 2$ is $2$.

Let's rewrite the equation

$\left(- 6 + 3\right) \cdot \left(4 - 3 \cdot 2\right) \div \left(2\right)$

Let's solve the LHS bracket.

$- 6 + 3 = - 3$

$- 3 \cdot \left(4 - 3 \cdot 2\right) \div \left(2\right)$

Now, the middle bracket.

$4 - 3 \cdot 2$ ←　 You have to multiply first
$4 - 6$
$- 2$

$- 3 \cdot - 2 \div \left(2\right)$
$6 \div 2$
$3$