What is complex conjugate of #2 - sqrt(2i)#?

1 Answer
Jul 31, 2018

Answer:

#2+sqrt2i#

Explanation:

#"Given a complex number "z=x+-yi#

#"then the complex conjugate is "x color(red)(∓)i#

#"note that the real part remains unchanged while the sign"#
#"of the imaginary part reverses"#

#"conjugate of "2-sqrt2i" is "2color(red)(+)sqrt2i#