Question

What is `cos^2theta-sin^3theta` in terms of non-exponential trigonometric functions?

Answer 1

`cos^2theta-sin^3theta`

`=1/2(1+cos2theta)-1/4(3sintheta-sin3theta)`

Using identities

`cos2theta=2cos^2theta-1`

And

`sin3theta=3sintheta-4sin^3theta`