What is $csc^2theta-sec^2theta+cos^3theta$ in terms of non-exponential trigonometric functions?

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Answer 1 · 2016-09-24T08:36:55

Using the following identities here

1) $sin^2theta=1/2(1-cos2theta)$

2) $cos^2theta=1/2(1+cos2theta)$

3) $cos^3theta=1/4(cos3theta+3costheta)$

$csc^2theta-sec^2theta+cos^3theta$

$=1/sin^2theta-1/cos^2theta+cos^3theta$

$=2/(1-cos2theta)-2/(1+cos2theta)+1/4(cos3theta+3costheta)$

What is csc^2theta-sec^2theta+cos^3thetacsc^2theta-sec^2theta+cos^3theta in terms of non-exponential trigonometric functions?