What is #(f/g)(-2)# when #f(x)=4x-6# and #g(x) = 4x^2+14x+2#?

1 Answer
Noah G
Nov 8, 2016

#(f/g)(-2) = 5/17#

Explanation:

#(f/g)(x) = (4x - 6)/(4x^2 + 14x + 2)#

#(f/g)(x) = (2(x - 3))/(2(x^2 + 7x + 1))#

#(f/g)(x) = (x- 3)/(x^2 + 7x + 1)#

#(f/g)(2) = (-2 - 3)/(-2^2 - 14 + 1)#

#(f/g)(2) = (-5)/(-17)#

#(f/g)(2) = 5/17#

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