Question

What is `f(x) = int 8x-1 dx` if `f(0)=12`?

Answer 1

`f(x)=4x^2-x+12`

Explanation:

By using normal rules of integration we can evaluate it as

`f(x)=int(8x-1)dx`

`=4x^2-x+C`.

But since the initial boundary condition was given, we may substitute it in to find

`f(0)=12iffC=12`

Therefore the required function is

`f(x)=4x^2-x+12`.