What is Hubble's constant in light years? Astronomy Scale and History of the Universe Expansion of the Universe 1 Answer A. S. Adikesavan Aug 24, 2016 Hubble constant #H_o = 71# km /sec/mega parsec = #4.5 X 10^(-12)# light year/sec/mega parsec. Explanation: Hubble constant #H_o = 71# km /sec/mega parsec #71 km # #= 71/499792=1.42 X 10^(-4)# light seconds #=1.42 X 10^(-4)/(365.256 X 24 X 60 X 60)# # = 4.5 X 10^(-12)# light years. S0, #H_o = 4.5X 10^(-12)# light years/sec/mega parsec.. . Answer link Related questions Why does intergalactic space expand, but not not galaxies and solar systems themselves? How fast in parsecs is the universe expanding? What is Hubble's Law? How do we know Hubble's Constant? How does Hubble Law relate distance to velocity? How does Hubble's Law change in an accelerating universe? How does Hubble's Law relate to redshift? How does Hubble's Law relate to the Big Bang Theory? If the universe is expanding, what is it expanding into? Will the universe explode? See all questions in Expansion of the Universe Impact of this question 3673 views around the world You can reuse this answer Creative Commons License