Question

What is `sec^2theta-csc^2theta` in terms of non-exponential trigonometric functions?

Answer 1

`(sectheta+csctheta)(sectheta-csctheta)`

Explanation:

This is a difference of squares.

The general rule is that `a^2-b^2=(a+b)(a-b)`.

Because of this:

`sec^2theta-csc^2theta=(sectheta+csctheta)(sectheta-csctheta)`