# What is the amplitude, period and the phase shift of y=12 cos 3(x-theta/2)?

$12 , \frac{2 \setminus \pi}{3} , - \frac{3 \setminus \theta}{2}$

#### Explanation:

The given trigonometric function

$y = 12 \setminus \cos 3 \left(x - \setminus \frac{\theta}{2}\right)$

$y = 12 \setminus \cos \left(3 x - \frac{3 \setminus \theta}{2}\right)$

Amplitude $= 12$

Period $= \frac{2 \setminus \pi}{3}$

Phase shift $= - \frac{3 \setminus \theta}{2}$