# What is the amplitude, period and the phase shift of y=- 2/3 sin πx?

Nov 6, 2015

Amplitude: $\frac{2}{3}$
Period: $2$
Phase shift: ${0}^{\setminus} \circ$

#### Explanation:

A wave function of the form $y = A \cdot \sin \left(\setminus \omega x + \setminus \theta\right)$ or $y = A \cdot \cos \left(\setminus \omega x + \setminus \theta\right)$ has three parts:

1. $A$ is the amplitude of the wave function. It does not matter if the wave function has a negative sign, amplitude is always positive.

2. $\setminus \omega$ is the angular frequency in radians.

3. $\theta$ is the phase shift of the wave.

All you have to do is identify these three parts and you're almost done! But before that, you need to transform your angular frequency $\omega$ to the period $T$.

$T = \setminus \frac{2 \pi}{\omega} = \setminus \frac{2 \pi}{\pi} = 2$