What is the amplitude, period and the phase shift of # y=tan 2x#?

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Answer 1 · 2018-06-20T06:08:52

Please see the explanation below

The amplitude of #tan2x# is #RR#

The period of a periodic function #f(x)# is such that

#f(x)=f(x+T)#

Here,

#f(x)=tan2x#

Therefore,

#tan2x=tan2(x+T)=tan(2x+2T)#

#=(tan2x+tan2T)/(1-tan2xtan2T)#

So,

#tan(2T)=0#

#=>#, #2T=pi#

#=>#, #T=pi/2#

The period is #T=pi/2#

There is no phase shift.

graph{tan(2x) [-7.9, 7.9, -3.95, 3.95]}