What is the angle between two of the carbon-chlorine bonds in the carbon tetrachloride (C CI_4 molecule)?

Nov 21, 2016

Answer:

The $\angle C l - C - C l$ bonds angles are all ${109.5}^{\circ}$ in $\text{carbon tetrachloride.}$

Explanation:

There are 4 bonding orbitals, 4 bonding electron pairs, around the central carbon in $\text{carbon tet}$. The bonding orbitals are arranged in a tetrahedron to give a molecule with tetrahedral geometry.

What is the equivalent angle in methane, $C {H}_{4}$?