What is the angular momentum of a gyroscope that is a solid cylinder with a radius of .24 m, a mass of 15 kg and a angular velocity of 140 rad/sec?

1 Answer
Sep 11, 2015

Answer:

#vec L=Ixxvec omega#
or
#L=Ixxomega =60.48 kg m^2 s^-1#

Explanation:

The moment of inertia #I# for a solid cylinder is #1/2mr^2#.

Substitute into the equation #L=Ixxomega# to get;

#L=1/2mr^2omega#.

Crunch in the numbers and you should get #60.48kg m^2 s^-1#.

The formula for moment of inertia can be derived by exploiting the definition of moment of inertia, #I=ointr^2dm#.

Hope this helps. I would be happy to explain more on the derivation if you want. Cheers.