What is the angular momentum of a rod with a mass of #2 kg# and length of #5 m# that is spinning around its center at #3 Hz#?

1 Answer
Apr 2, 2017

Answer:

The angular momentum is #=78.5kgm^2s^-1#

Explanation:

The angular momentum is #L=Iomega#

where #I# is the moment of inertia

and #omega# is the angular velocity

The moment of inertia of a rod, rotating about the center is

#I=1/12*mL^2#

#=1/12*2*5^2= 25/6 kgm^2#

The angular velocity is #omega=3*2pi rads^-1#

The angular momentum is

#L=25/6*6pikgm^2s^-1#

#=25pikgm^2s^-1#

#=78.5kgm^2s^-1#