What is the angular momentum of a rod with a mass of #2 kg# and length of #7 m# that is spinning around its center at #3 Hz#?

1 Answer
Mar 22, 2017

Answer:

The angular momentum is #=153.9kgm^2s^-1#

Explanation:

The angular momentum is #L=Iomega#

where #I# is the moment of inertia

and #omega# is the angular velocity

The moment of inertia of a rod, rotating about the center is

#I=1/12*mL^2#

#=1/12*2*7^2= 49/6 kgm^2#

The angular velocity is

#omega=3*2pi=(6pi) rads^-1#

The angular momentum is

#L=49/6*(6pi)=153.9kgm^2s^-1#