What is the angular momentum of a rod with a mass of #2 kg# and length of #9 m# that is spinning around its center at #3 Hz#?

1 Answer
Jun 4, 2017

Answer:

The angular momentum is #=254.5kgm^2s^-1#

Explanation:

The angular momentum is #L=Iomega#

where #I# is the moment of inertia

and #omega# is the angular velocity

The moment of inertia of a rod, rotating about the center is

#I=1/12*mL^2#

#=1/12*2*9^2= 13.5 kgm^2#

The angular velocity is

#omega=3*2pi=6pirads^-1#

The angular momentum is

#L=I omega=13.5*6pi=254.5kgm^2s^-1#