What is the angular momentum of a rod with a mass of # 6 kg# and length of #4 m# that is spinning around its center at #3 Hz#?

1 Answer
Dec 16, 2017

Answer:

The angular momentum is #=150.8kgm^2#

Explanation:

The angular momentum is #L=Iomega#

where #I# is the moment of inertia

and #omega# is the angular velocity

The moment of inertia of a rod, rotating about the center is

#I=1/12*mL^2#

The mass of the rod is #m=6kg#

The length of the rod is #L=4m#

Therefore, the moment of inertia is

#L=1/12*6*4^2= 8 kgm^2#

The frequency is #f=3Hz#

The angular velocity is #omega=2*pi*f=6pi#

Then,

The angular momentum is

#L=Iomega=8*6pi=48pi=150.8kgm^2#