What is the angular momentum of a rod with a mass of  6 kg and length of 4 m that is spinning around its center at 15 Hz?

Jan 29, 2017

The angular momentum is $= 754 k g m {s}^{- 1}$

Explanation:

The angular momentum is $L = I \omega$

where $I$ is the moment of inertia

For a rod, $I = \frac{m {L}^{2}}{12}$

So, $I = 6 \cdot {\left(4\right)}^{2} / 12 = 8 k g {m}^{2}$

$\omega = 15 \cdot 2 \pi = 30 \pi r a {\mathrm{ds}}^{-} 1$

$L = 8 \cdot 30 \pi = 754 k g m {s}^{- 1}$