What is the angular momentum of a rod with a mass of # 8 kg# and length of #4 m# that is spinning around its center at #8 Hz#?

1 Answer
Dec 10, 2017

Answer:

The angular momentum is #=536.2kgm^2#

Explanation:

The angular momentum is #L=Iomega#

where #I# is the moment of inertia

and #omega# is the angular velocity

The moment of inertia of a rod, rotating about the center is

#I=1/12*mL^2#

The mass of the rod is #m=8kg#

The length of the rod is #L=4m#

Therefore, the moment of inertia is

#L=1/12*8*4^2= 10.67 kgm^2#

The frequency is #f=8Hz#

The angular velocity is #omega=2*pi*f=16pi#

Then,

The angular momentum is

#L=Iomega=10.67*16pi=536.2kgm^2#