Question

What is the angular momentum of an object with a mass of `5 kg` that moves along a circular path of radius `3 m` at a frequency of `18 Hz`?

Answer 1

`5089.38\ "kg m"^2//"s"`

Explanation:

Angular momentum (`L`) is given as

`L = I ω`

`L = mr^2 × 2 π f`

Moment of inertia of small object is `mr^2`; `omega = 2 π f`

`L = "5 kg" × ("3 m")^2 × 2 × π × "18 Hz" = 5089.38\ "kg m"^2//"s"`

Answer 2

The angular momentum is `=5089.4kgm^2s^-1`

Explanation:

The angular momentum is `L=Iomega`

where `I` is the moment of inertia

The mass of the object is `m=5kg`

The radius of the path is `r=3m`

The moment of inertia of the object is given by

`I=mr^2`

`=5*3^2= 45 kgm^2`

The frequency is `f=18Hz`

The angular velocity is `omega=2pif=2*18*pi=36pirads^-1`

The angular momentum is

`L=Iomega=45*36pi=5089.4kgm^2s^-1`