# What is the angular momentum of an object with a mass of 5 kg that moves along a circular path of radius 9 m at a frequency of  2/9 Hz ?

## I

Dec 27, 2016

The answer is $= 50 \pi = 157.1 k g m {s}^{- 1}$

#### Explanation:

The angular momentum is $L = I \omega$

where $I$ is the moment of inertia

For a solid disc, $I = \frac{m {r}^{2}}{2}$

So, $I = 5 \cdot {\left(9\right)}^{2} / 2 = \frac{225}{2} k g {m}^{2}$

$\omega = \frac{2}{9} \cdot 2 \pi = \frac{4}{9} \pi r a {\mathrm{ds}}^{- 1}$

$L = \frac{225}{2} \cdot \frac{4}{9} \pi = 50 \pi = 157.1 k g m {s}^{- 1}$