# What is the angular momentum of an object with a mass of 5 kg that moves along a circular path of radius 8 m at a frequency of  12 Hz ?

Dec 19, 2015

$2.41 \times {10}^{4} {\text{kg.m"^(2)."s}}^{- 1}$

#### Explanation:

For circular motion the angular momentum $L$ is given by:

$L = m \times v \times r$

$f = 12 \text{Hz}$

This means 12 revolutions per second. The time period $T$ is given by:

$T = \frac{1}{f} = \frac{1}{12} \text{s}$

The distance travelled =$2 \pi r$

So the velocity =$\frac{2 \pi r}{T} = \frac{2 \times \pi \times 8}{\frac{1}{12}} = 192 \pi$

$\therefore L = 5 \times 192 \pi \times 8 = 2.41 \times {10}^{4} {\text{kg.m"^(2)."s}}^{- 1}$