# What is the antiderivative of -5e^(x-1)?

I found: $- 5 {e}^{x - 1} + c$
$\int - 5 {e}^{x - 1} \mathrm{dx} = - 5 \int {e}^{x - 1} \mathrm{dx} =$
but $d \left[\left(x - 1\right)\right] = \mathrm{dx}$ so you can write:
$- 5 \int {e}^{x - 1} d \left(x - 1\right) =$
$= - 5 {e}^{x - 1} + c$