What is the approximate density of a mineral with a mass of 262.2 grams that displaces 46 cubic centimeters of water? Chemistry Measurement Density 1 Answer Andy Y. May 21, 2017 Answer: #d=5.7 " g"/"cm"^3# Explanation: #d=#? #m=262.2" g"# The volume of the mineral is equal to the volume of water it displaced, because the density of water is #1" g"//"cm"^3# #V=46 " cm"^3# Formula for density is #d=m/V=(262.2" g")/(46 " cm"^3)=5.7 " g"/"cm"^3# Related questions How can density be used to identify substances? How can you find mass from density? How are density mass and volume related? How do you calculate mass using density and volume? How do you convert mass to density? How do you determine the density of a gas? What is the density of water? What is linear mass density? Why does density change with temperature? How does density affect ocean currents? See all questions in Density Impact of this question 3431 views around the world You can reuse this answer Creative Commons License