Question

What is the approximate density of a mineral with a mass of 262.2 grams that displaces 46 cubic centimeters of water?

Answer 1

`d=5.7 " g"/"cm"^3`

Explanation:

`d=`?
`m=262.2" g"`

The volume of the mineral is equal to the volume of water it displaced, because the density of water is `1" g"//"cm"^3`
`V=46 " cm"^3`

Formula for density is

`d=m/V=(262.2" g")/(46 " cm"^3)=5.7 " g"/"cm"^3`