# What is the area enclosed by #r=-cos(theta-(7pi)/4) # between #theta in [4pi/3,(5pi)/3]#?

##### 1 Answer

Feb 17, 2017

#### Explanation:

The graph is a circle of radius 1/2, through pole, with center on

Despite that the non-negative r = sqrt(x^2+y^2) is

the higher limit

graph{(sqrt2(x^2+y^2)+x+y)(y+sqrt3x)(y-sqrt3x)=0 [-2.5, 2.5, -1.25, 1.25]}

Area=

from