# What is the axis of symmetry and vertex for the graph #f(x)=-3x^2+6x+12#?

##### 2 Answers

**Axis of symmetry is** **vertex is at**

#### Explanation:

Here

Axis of symmetry is

graph{-3x^2+6x+12 [-40, 40, -20, 20]} [Ans]

#### Explanation:

#"for a parabola in standard form " y=ax^2+bx+c#

#"the x-coordinate of the vertex is " x_(color(red)"vertex")=-b/(2a)#

#y=-3x^2+6x+12" is in standard form"#

#"with " a=-3, b=6" and " c=12#

#rArrx_(color(red)"vertex")=-6/(-6)=1#

#"substitute this value into function for y-coordinate"#

#y_(color(red)"vertex")=-3+6+12=15#

#rArrcolor(magenta)"vertex "=(1,15)#

#"since " a<0" then graph has a maximum " nnn#

#"the axis of symmetry passes through the vertex "#

#rArrx=1" is equation of axis of symmetry"#

graph{(y+3x^2-6x-12)(y-1000x+1000)=0 [-40, 40, -20, 20]}