Question

What is the axis of symmetry and vertex for the graph `f(x)=4x^2-8x+3`?

Answer 1

Vertex (1, -1)

Explanation:

x-coordinate of vertex and axis of symmetry:
`x = -b/(2a) = 8/8 = 1`
y-coordinate of vertex:
y(1) = 4 - 8 + 3 = -1
Vertex (1, -1)
graph{4x^2 - 8x + 3 [-5, 5, -2.5, 2.5]}