Question

What is the axis of symmetry and vertex for the graph `f(x)= x^2 + 1`?

Answer 1

Vertex is at `(0,1)` and axis of symmetry is `x=0`

Explanation:

`f(x)= x^2+1 or y=(x-0)^2+1` . Comparing with the

equation of parabola in vertex form is `y=a(x-h)^2+k ; (h,k)`

being vertex , we find here `h=0, k=1`. So vertex is at `(0,1)`.

Axis of symmetry is `x=h or x=0`

graph{x^2+1 [-10, 10, -5, 5]}