What is the axis of symmetry and vertex for the graph #f(x)= x^2 - 10x + 5#?

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Answer 1 · 2017-05-15T15:06:03

Axis of symmetry is #x =5# and the vertex is #(5,-20)#

#f(x) = x^2 -10x+5#

Find the axis of symmetry using: #x = (-b)/(2a)#

#x = (-(-10))/(2(1)) = 10/2 =5#

The vertex lies on the vertical line where #x=5#, find the #y:#

#y = 5^2 -10(5) +5#

#y= 25-50+5#

#y = -20#

The vertex (or minimum Turning Point) is at #(5,-20)#