# What is the axis of symmetry and vertex for the graph f(x) = x^2 - 4x?

Axis is x = 2 and vertex is (2, $-$4 )
${\left(x - 2\right)}^{2}$ = y + 4 = 4 x 1/4 X ( y + 4.)
The focus is at $\left(2 , - 4 + \frac{1}{4}\right)$= ( 2, $-$15/4 ).