What is the axis of symmetry and vertex for the graph #y= 1/2x^2#?

1 Answer
turksvids
Jan 3, 2018

The vertex is #(0,0)# and the axis of symmetry is #x=0#.

Explanation:

The function #y=1/2x^2# is in the form #y=a*(x-h)^2+k# which has vertex #(h,k)#. The axis of symmetry is the vertical line through the vertex, so #x=h#.

Going back to the original #y=1/2x^2#, we can see by inspection that the vertex is #(0,0)#. The axis of symmetry, therefore, is #x=0#.

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