# What is the axis of symmetry and vertex for the graph y=-2(x+3)^2+1?

Axis of symmetry is $x = - 3$
Vertex $\left(- 3 , 1\right)$

#### Explanation:

From the given equation
$y = - 2 {\left(x + 3\right)}^{2} + 1$

We adjust the equation so that it appears as follows

${\left(x - - 3\right)}^{2} = - \frac{1}{2} \left(y - 1\right)$

by inspection, we can see that the vertex of the parabola is at $\left(- 3 , 1\right)$ and we take the value of h to determine our

axis of symmetry

$x = - 3$

see the graph of $y = - 2 {\left(x + 3\right)}^{2} + 1$ with the axis of symmetry $x = - 3$.

graph{(y+2(x+3)^2-1)(y+1000000x+3*1000000)=0[-20,20,-10,10]}

God bless... I hope the explanation is useful..