What is the axis of symmetry and vertex for the graph #y=-2(x+3)^2+1#?

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Answer 1 · 2016-02-27T08:15:35

Axis of symmetry is #x=-3#
Vertex #(-3, 1)#

From the given equation
#y=-2(x+3)^2+1#

We adjust the equation so that it appears as follows

#(x--3)^2=-1/2(y-1)#

by inspection, we can see that the vertex of the parabola is at #(-3,1)# and we take the value of h to determine our

axis of symmetry

#x=-3#

see the graph of #y=-2(x+3)^2+1# with the axis of symmetry #x=-3#.

graph{(y+2(x+3)^2-1)(y+1000000x+3*1000000)=0[-20,20,-10,10]}

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