What is the axis of symmetry and vertex for the graph #y=-2x^2+5x-4#?

1 Answer
Apr 17, 2018

See below

Explanation:

From the general quadratic #y=ax^2+bx +c# the x coordinate of the vertex is given by #-b/(2a)#

#=># #-5/(2xx-2)# =#5/4#

So the line of symmetry is #x=5/4#

To find the vertex, #y=-2xx(5/4)^2+5xx5/4-4#

#=># #y=-50/(16)+25/4-4# , #y=34/(16)# #y=17/8#

The graph is an #n# shaped parabola because it is a negative #x^2#, so the vertex is a maximum at #(5/4,17/8)#