What is the axis of symmetry and vertex for the graph #y=-3(x+2)^2+5#?

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Answer 1 · 2017-08-04T17:22:48

vertex: #(-2,5)#
axis of symmetry: #x=-2#

You can write a quadratic equation in standard form:

#y=ax^2+bx+c#

or in vertex form:

#y=a(x-h)^2+k#

where #(h,k)# is the vertex of the graph (parabola) and #x=h# is the axis of symmetry.

The equation

#y=-3(x+2)^2+5#

is already in vertex form so the vertex is #(-2,5# and the axis of symmetry is #x=-2#.