Question

What is the axis of symmetry and vertex for the graph `y=8(x-10)^2-16`?

Answer 1

Vertex is at `(10 ,-16)`
Axis of symmetry is `x= 10`

Explanation:

`y= 8(x-10)^2 -16` . Comparing with standard vertex form of

equation `y=a(x-h)^2+k ; (h,k)` being vertex , we find here

`h=10 ,k=-16` . So vertex is at `(10 ,-16)`

Axis of symmetry is `x= h or x= 10`

graph{8(x-10)^2-16 [-40, 40, -20, 20]} [Ans]