What is the axis of symmetry and vertex for the graph #y = x^2 – 4x + 2#?

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Answer 1 · 2016-08-25T04:26:50

Vertex #(2,-2)#

axis of symmetry #x=2#

Given -

#y=x^2-4x+2#

Vertex

#x=(-b)/(2a)=(-(-4))/(2xx1)=4/2=2#

At #x=2; y=2^2-4(2)+2#

#y=4-8+2=-2#

Vertex #(2,-2)#

axis of symmetry #x=2#

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