What is the binomial expansion of (2 + 3x)^-2? Precalculus The Binomial Theorem Pascal's Triangle and Binomial Expansion 1 Answer cspark1981 Nov 1, 2015 (2+3x)^(-2) = 1/4(1 - 3x + 27/4x^2 + ...) when |x| < 2/3 Explanation: When |x| < 1 (1+x)^n = 1 + n/(1!)x + (n(n-1))/(2!)x^2 + (n(n-1)(n-2))/(3!)x^3 + ... (2+3x)^(-2) = 1/4(1+3/2x)^(-2) = 1/4(1 - 2 \times 3/2x + 3 \times (3/2x)^2 + ...) when |x| < 2/3 = 1/4(1 - 3x + 27/4x^2 + ...) when |x| < 2/3 Answer link Related questions What is Pascal's triangle? How do I find the nth row of Pascal's triangle? How does Pascal's triangle relate to binomial expansion? How do I find a coefficient using Pascal's triangle? How do I use Pascal's triangle to expand (2x + y)^4? How do I use Pascal's triangle to expand (3a + b)^4? How do I use Pascal's triangle to expand (x + 2)^5? How do I use Pascal's triangle to expand (x - 1)^5? How do I use Pascal's triangle to expand a binomial? How do I use Pascal's triangle to expand the binomial (a-b)^6? See all questions in Pascal's Triangle and Binomial Expansion Impact of this question 11306 views around the world You can reuse this answer Creative Commons License