# What is the Cartesian form of (-10,(13pi)/16)?

Apr 15, 2017

$\left(8.315 , 5.556\right)$

#### Explanation:

Use the parametric form to find the $x$ and $y$ points. To convert from polar to parametric form, use these equations:

$x \left(t\right) = r \cos \left(\theta\right)$

$y \left(t\right) = r \sin \left(\theta\right)$

From our point, we can see that $r = - 10$ and $\theta = 13 \frac{\pi}{16}$. Plug into our formulas:

$x \left(13 \frac{\pi}{16}\right) = - 10 \cos \left(16 \frac{\pi}{16}\right) \approx 8.315$

$y \left(13 \frac{\pi}{16}\right) = - 10 \sin \left(16 \frac{\pi}{16}\right) \approx - 5.556$

So our point is $\left(8.315 , 5.556\right)$