# What is the Cartesian form of (-17,(-3pi)/6))?

May 15, 2017

$\left(0 , 17\right)$

#### Explanation:

To write a polar point into cartesian form, we convert it into the parametric form using these equations:

$x = r \cos \theta$
$y = r \sin \theta$

$r = - 17$ and $\theta = \frac{- 3 \pi}{6}$ Plug into these equations:

$x = - 17 \cos \left(- \frac{\pi}{2}\right) = 0$
$y = - 17 \sin \left(- \frac{\pi}{2}\right) = 17$

So we have $x = 0$ and $y = 17$. Write this as a point:

$\left(0 , 17\right)$