# What is the Cartesian form of (49,(2pi)/4)?

Jul 28, 2017

$\left(0 , 49\right)$

#### Explanation:

We're asked to find the Cartesian (rectangular) form of a polar coordinate.

We can use the following two equations:

$x = r \cos \theta$

$y = r \sin \theta$

Here,

• $r = 49$

• $\theta = \frac{2 \pi}{4} = \frac{\pi}{2}$

Thus, we have

x = 49cos(pi/2) = color(red)(0

y = 49sin(pi/2) = color(blue)(49

The coordinate point is therefore

$\left(\textcolor{red}{0} , \textcolor{b l u e}{49}\right)$