# What is the center and radius of the circle with equation x^2 + (y + 6)^2 = 49?

Center $\left(0 , - 6\right)$ and Radius$= 7$

#### Explanation:

We can transform first to the center-radius form first for proper visibility

${x}^{2} + {\left(y + 6\right)}^{2} = 49$

${\left(x - 0\right)}^{2} + {\left(y - - 6\right)}^{2} = {7}^{2}$
now it takes the form
${\left(x - h\right)}^{2} + {\left(y - k\right)}^{2} = {r}^{2}$

so that, just by inspection, it is now clear that

Center $\left(0 , - 6\right)$ and Radius$= 7$

graph{(x-0)^2+(y--6)^2=7^2[-20,20,-18,2]}

God bless...I hope the explanation is useful...