What is the centroid of a triangle with corners at #(2 , 5 )#, #(4 ,7 )#, and #(2 , 7 )#?

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Answer 1 · 2016-03-17T11:57:47

Centroid of the triangle is at #(8/3,19/3)#.

Centroid of a triangle with corners at #(x_1,y_1)#, #(x_2,y_2)# and #(x_3,y_3)# is given by

#(1/3xx(x_1+x_2+x_3),1/3xx(y_1+y_2+y_3))#

Hence, centroid of the triangle with corners at #(2,5)#, #(4,7)# and #(2,7)# is

#(1/3xx(2+4+2),1/3xx(5+7+7))# or #(8/3,19/3)#