What is the charge on the complex ion in #Ca_2[Fe(CN)_6]#?

1 Answer
Jul 29, 2016

Answer:

As written, you have an #[Fe(C-=N)_6]^(-4)# complex ion.

Explanation:

Calcium metal typically forms the #Ca^(2+)# ion. If this is a real compound (and not a typo), you thus have a #Fe(II+)# centre. The charge of the complex as written is of course zero. Why?

I would check your source.